WebIf AC = 5.7 cm, BD = 3.8 cm and CD = 5.4 cm, Find BC. Solution: Given: BD ⊥ AC AC = 5.7 cm, BD = 3.8 cm and CD = 5.4 cm ∠ABC = 90 o Required to find: BC We know that, ΔABC ∼ ΔBDC [By AA similarity] ∠BCA = ∠DCA = 90 o ∠AXY = ∠ABC [Common] Thus, AB/ BD = BC/ CD [Corresponding Parts of Similar Triangles are propositional] 5.7/ 3.8 = BC/ 5.4 WebMar 29, 2024 · Example 12 In figure, if AD BC, prove that AB2 + CD2 = BD2 + AC2. Given: where AD BC To Prove:- AB2 + CD2 = BD2 + AC2 Proof: Since AC BD ADC = ADB = 90 …

Exercise -10.1 Prove that segment DE BC.

WebSolution. Given: ∠ACB = 90 0 and CD ⊥ AB. To Prove: BC 2 AC 2 = BD AD. Proof: In ACB and CDB. ∠ ACB = ∠ CDB = 90 ∘ (Given) ∠ ABC = ∠ CBD (Common) By AA similarity-criterion … WebIn Fig. 5.10, if AC = BD, then prove that AB = CD. From the above figure we get that AC = AB + BC BD = BC + CD It is given that AC = BD Plug the value of AC we get AB + BC = BC + CD … prime now credit card

In Fig., if AB = AC, prove that BE = EC - Mathematics

WebSolution Given that : CD ⊥ AB ∠ACB = 90° To Prove : CD 2 = BD x AD Using Pythagoras Theorem in ΔACD AC 2 = AD 2 + CD 2 .... (1) Using Pythagoras Theorem in ΔCDB CB 2 = … WebMar 29, 2024 · Ex 6.5,3 In figure, ABD is a triangle right angled at A and AC ⊥ BD. Show that AB2 = BC . BD Given: ABD is a triangle right angled at A . & AC ⊥ 𝐵𝐷 To prove: AB2 = BC . WebApr 10, 2024 · In Fig. 10.22, the sides BA and CA have been produced such that: BA = AD and CA = AE. ... and AB . Then, E, and CF are medians of ' ABC . Now, D is midpoint of BC 2 BC C Similarly, 2 AC CE EA 2 AB AF FB Since ' ABC is an equilateral triangle A «« 2 2 2 BC AC AB BD DC CE EA AF FB «« And also, qAB 60 «« Now, consider ' ABD and ... prime now customer service phone number